madey21
Answered

$
2 \text{HCl} + \text{Mg} \rightarrow \text{MgCl}_2 + \text{H}_2
$

The initial temperature of the [tex]$41.3 \, g$[/tex] of solution is [tex]$21.2^{\circ} \text{C}$[/tex]. The temperature is [tex]$76.6^{\circ} \text{C}$[/tex] at the end of the reaction. What is the heat change for the solution?

$
\begin{aligned}
& c_{\text{soln}} = 4.04 \, \text{J/g}^{\circ}\text{C} \\
& q_{\text{soln}} = m \times c \times (T_f - T_i) \\
& q_{\text{soln}} = 41.3 \times 4.04 \times (76.6 - 21.2)
\end{aligned}
$



Answer :

Sure! Let's walk through the problem step by step to find the heat change for the solution.

### Given Data:

1. Mass of the solution (m): \( 41.3 \, \text{g} \)
2. Specific heat capacity (c): \( 4.04 \, \text{J/g}^\circ\text{C} \)
3. Initial Temperature (T_initial): \( 21.2^\circ\text{C} \)
4. Final Temperature (T_final): \( 76.6^\circ\text{C} \)

### Formula for Heat Change:

The heat change for the solution can be calculated using the formula:
[tex]\[ q_{\text{soln}} = m \times c \times (T_f - T_i) \][/tex]

### Step-by-Step Solution:

1. Determine the temperature change (ΔT):
[tex]\[ ΔT = T_{\text{final}} - T_{\text{initial}} \][/tex]
[tex]\[ ΔT = 76.6^\circ\text{C} - 21.2^\circ\text{C} \][/tex]
[tex]\[ ΔT = 55.4^\circ\text{C} \][/tex]

2. Substitute the values into the formula:
[tex]\[ q_{\text{soln}} = 41.3 \, \text{g} \times 4.04 \, \text{J/g}^\circ\text{C} \times 55.4^\circ\text{C} \][/tex]

3. Calculate the heat change (q_soln):
[tex]\[ q_{\text{soln}} = 41.3 \times 4.04 \times 55.4 \][/tex]

4. The multiplication yields:
[tex]\[ q_{\text{soln}} = 9243.600799999998 \, \text{J} \][/tex]

### Final Result:

The heat change for the solution is [tex]\( 9243.600799999998 \, \text{J} \)[/tex].

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