What is the \(x\)-intercept of the graph of the function \(f(x) = x^2 - 16x + 64\)?

A. \((-8, 0)\)
B. \((0, 8)\)
C. \((8, 0)\)
D. [tex]\((0, -8)\)[/tex]



Answer :

To find the \( x \)-intercept of the function \( f(x) = x^2 - 16x + 64 \), we need to set the function equal to zero and solve for \( x \).

[tex]\[ f(x) = x^2 - 16x + 64 \][/tex]

Step-by-step solution:

1. Set the function equal to zero:
[tex]\[ x^2 - 16x + 64 = 0 \][/tex]

2. Factor the quadratic expression:
The quadratic expression can be factored as:
[tex]\[ (x - 8)^2 = 0 \][/tex]

3. Solve for \( x \):
Since \((x - 8)^2 = 0\), we have:
[tex]\[ x - 8 = 0 \implies x = 8 \][/tex]

The \( x \)-intercept is the point where the graph crosses the \( x \)-axis. For this quadratic function, the \( x \)-intercept will be at \( x = 8 \).

Hence, the \( x \)-intercept is:
[tex]\[ (8, 0) \][/tex]

Therefore, the correct answer is:
[tex]\[ (8, 0) \][/tex]

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