Answer :
To determine the net force acting on a car, we can utilize Newton's second law of motion, which states that the net force [tex]\( F \)[/tex] on an object is the product of its mass [tex]\( m \)[/tex] and its acceleration [tex]\( a \)[/tex]. Mathematically, this relationship is expressed as:
[tex]\[ F = m \times a \][/tex]
We are given:
- The mass of the car, [tex]\( m = 1.00 \times 10^3 \)[/tex] kilograms
- The acceleration of the car, [tex]\( a = 4.5 \)[/tex] meters per second squared
Substituting these values into the formula, we get:
[tex]\[ F = (1.00 \times 10^3 \text{ kg}) \times (4.5 \text{ m/s}^2) \][/tex]
Performing the multiplication:
[tex]\[ F = 1.00 \times 4.5 \times 10^3 \][/tex]
[tex]\[ F = 4.5 \times 10^3 \text{ N} \][/tex]
Thus, the net force on the car is:
[tex]\[ 4.5 \times 10^3 \text{ newtons} \][/tex]
The correct answer is:
C. [tex]\( 4.5 \times 10^3 \)[/tex] newtons
[tex]\[ F = m \times a \][/tex]
We are given:
- The mass of the car, [tex]\( m = 1.00 \times 10^3 \)[/tex] kilograms
- The acceleration of the car, [tex]\( a = 4.5 \)[/tex] meters per second squared
Substituting these values into the formula, we get:
[tex]\[ F = (1.00 \times 10^3 \text{ kg}) \times (4.5 \text{ m/s}^2) \][/tex]
Performing the multiplication:
[tex]\[ F = 1.00 \times 4.5 \times 10^3 \][/tex]
[tex]\[ F = 4.5 \times 10^3 \text{ N} \][/tex]
Thus, the net force on the car is:
[tex]\[ 4.5 \times 10^3 \text{ newtons} \][/tex]
The correct answer is:
C. [tex]\( 4.5 \times 10^3 \)[/tex] newtons
