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Roberto had $88, which is eleven times as much money as Bianca had. How much money did Bianca have? Select the correct solution method below, representing Bianca's money with [tex]$x[tex]$[/tex].

A. [tex]$[/tex]11x = 88$[/tex]. Divide both sides by 11. Bianca had [tex]$\[tex]$ 8$[/tex][/tex].

B. [tex]$\frac{r}{\Pi}=88$[/tex]. Multiply both sides by 11. Bianca had [tex][tex]$\$[/tex] 968$[/tex].

C. [tex]$x + 11 = 88$[/tex]. Subtract 11 from both sides. Bianca had [tex]$\[tex]$ 77$[/tex][/tex].

D. [tex]$x - 11 = 88$[/tex]. Add 11 to both sides. Bianca had [tex][tex]$\$[/tex] 99$[/tex].



Answer :

GinnyAnswer
Let's carefully examine the given problem and the available solution methods to determine the correct one.

The problem states that Roberto had [tex]$88, which is eleven times as much money as Bianca had. We need to determine how much money Bianca had. To represent Bianca's money, we use \( x \). Since Roberto’s money is eleven times Bianca’s money, we can write the equation: \[ 11x = 88 \] Now we need to solve this equation for \( x \): 1. Divide both sides of the equation by 11 to isolate \( x \): \[ x = \frac{88}{11} \] 2. Performing the division results in: \[ x = 8 \] Hence, Bianca had $[/tex]8.

The correct solution method is:
A. [tex]\( 11x = 88 \)[/tex]. Divide both sides by 11. Bianca had $8.

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