What is the product?

[tex]\[ (6r - 1)(-8r - 3) \][/tex]

A. [tex]\(-48r^2 - 10r + 3\)[/tex]
B. [tex]\(-48r^2 - 10r - 3\)[/tex]
C. [tex]\(-48r^2 + 3\)[/tex]
D. [tex]\(-48r^2 - 3\)[/tex]



Answer :

To find the product of the expressions [tex]\( (6r - 1) \)[/tex] and [tex]\( (-8r - 3) \)[/tex], we will use the distributive property of multiplication over addition, also known as the FOIL method for binomials. The steps are as follows:

1. First: Multiply the first terms in each binomial:
[tex]\[ 6r \times (-8r) = -48r^2 \][/tex]

2. Outer: Multiply the outer terms in the product:
[tex]\[ 6r \times (-3) = -18r \][/tex]

3. Inner: Multiply the inner terms in the product:
[tex]\[ -1 \times (-8r) = 8r \][/tex]

4. Last: Multiply the last terms in each binomial:
[tex]\[ -1 \times (-3) = 3 \][/tex]

Next, add these results together:
[tex]\[ -48r^2 + (-18r) + 8r + 3 \][/tex]

Combine like terms (the [tex]\( r \)[/tex] terms):
[tex]\[ -48r^2 + (-18r + 8r) + 3 = -48r^2 - 10r + 3 \][/tex]

Therefore, the product of [tex]\( (6r - 1)(-8r - 3) \)[/tex] is:
[tex]\[ -48r^2 - 10r + 3 \][/tex]

From the given options, the correct answer is:
[tex]\[ -48r^2 - 10r + 3 \][/tex]

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