Solve for [tex]x[/tex]:

[tex]\[ 3x = 6x - 2 \][/tex]



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[tex]$\operatorname{tg} 18^\circ + \operatorname{tg} 27^\circ + \operatorname{tg} 18^\circ \times \operatorname{tg} 27^\circ =$[/tex]
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Answer :

Let's solve the given trigonometric expression [tex]\(\operatorname{tg}(18^\circ) + \operatorname{tg}(27^\circ) + \operatorname{tg}(18^\circ) \times \operatorname{tg}(27^\circ)\)[/tex] step by step.

1. Calculate [tex]\(\operatorname{tg}(18^\circ)\)[/tex]:
The tangent of 18 degrees is approximately:
[tex]\[ \operatorname{tg}(18^\circ) \approx 0.3249196962329063 \][/tex]

2. Calculate [tex]\(\operatorname{tg}(27^\circ)\)[/tex]:
The tangent of 27 degrees is approximately:
[tex]\[ \operatorname{tg}(27^\circ) \approx 0.5095254494944288 \][/tex]

3. Calculate the product [tex]\(\operatorname{tg}(18^\circ) \times \operatorname{tg}(27^\circ)\)[/tex]:
[tex]\[ \operatorname{tg}(18^\circ) \times \operatorname{tg}(27^\circ) \approx 0.3249196962329063 \times 0.5095254494944288 \approx 0.16501791490974126 \][/tex]

4. Add the results:
Now we need to add these three terms together:
[tex]\[ \operatorname{tg}(18^\circ) + \operatorname{tg}(27^\circ) + \operatorname{tg}(18^\circ) \times \operatorname{tg}(27^\circ) \approx 0.3249196962329063 + 0.5095254494944288 + 0.16501791490974126 \][/tex]

Combining these, we get:
[tex]\[ 0.3249196962329063 + 0.5095254494944288 + 0.16501791490974126 \approx 0.9999999999999999 \][/tex]

Hence, the final result for the given expression [tex]\(\operatorname{tg}(18^\circ) + \operatorname{tg}(27^\circ) + \operatorname{tg}(18^\circ) \times \operatorname{tg}(27^\circ)\)[/tex] is approximately:
[tex]\[ \boxed{1} \][/tex]

Answer:

the answer for first ques will be 2/3

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