Answer :
Sure, let's go through the detailed step-by-step solution to find out the simple interest Deepika needs to pay.
1. Principal (P): This is the amount borrowed, which is Rs 1,30,000.
2. Rate of Interest (R): This is the annual interest rate. The given rate is [tex]\( 21\% \)[/tex] per annum.
3. Time (T): The duration for which the money is borrowed is given as 1 year and 6 months. To convert this into years, we note that:
[tex]\[ 1 \text{ year and 6 months} = 1 + \frac{6}{12} = 1 + 0.5 = 1.5 \text{ years} \][/tex]
4. Calculate Simple Interest (SI): The formula for simple interest is given by:
[tex]\[ \text{SI} = P \times R \times T \][/tex]
Plugging in the values:
[tex]\[ P = 1,30,000 \text{ Rs} \][/tex]
[tex]\[ R = 21\% = \frac{21}{100} = 0.21 \][/tex]
[tex]\[ T = 1.5 \text{ years} \][/tex]
Substituting these into the formula:
[tex]\[ \text{SI} = 1,30,000 \times 0.21 \times 1.5 \][/tex]
5. Calculation:
- First, calculate [tex]\( 1,30,000 \times 0.21 \)[/tex]:
[tex]\[ 1,30,000 \times 0.21 = 27,300 \][/tex]
- Then, multiply that result by 1.5:
[tex]\[ 27,300 \times 1.5 = 40,950 \][/tex]
Therefore, the simple interest (SI) that Deepika will have to pay at the end of 1 year and 6 months is Rs 40,950.
So, the correct option is:
b. Rs 40,950
1. Principal (P): This is the amount borrowed, which is Rs 1,30,000.
2. Rate of Interest (R): This is the annual interest rate. The given rate is [tex]\( 21\% \)[/tex] per annum.
3. Time (T): The duration for which the money is borrowed is given as 1 year and 6 months. To convert this into years, we note that:
[tex]\[ 1 \text{ year and 6 months} = 1 + \frac{6}{12} = 1 + 0.5 = 1.5 \text{ years} \][/tex]
4. Calculate Simple Interest (SI): The formula for simple interest is given by:
[tex]\[ \text{SI} = P \times R \times T \][/tex]
Plugging in the values:
[tex]\[ P = 1,30,000 \text{ Rs} \][/tex]
[tex]\[ R = 21\% = \frac{21}{100} = 0.21 \][/tex]
[tex]\[ T = 1.5 \text{ years} \][/tex]
Substituting these into the formula:
[tex]\[ \text{SI} = 1,30,000 \times 0.21 \times 1.5 \][/tex]
5. Calculation:
- First, calculate [tex]\( 1,30,000 \times 0.21 \)[/tex]:
[tex]\[ 1,30,000 \times 0.21 = 27,300 \][/tex]
- Then, multiply that result by 1.5:
[tex]\[ 27,300 \times 1.5 = 40,950 \][/tex]
Therefore, the simple interest (SI) that Deepika will have to pay at the end of 1 year and 6 months is Rs 40,950.
So, the correct option is:
b. Rs 40,950
