Answer :
To determine for which vitamins Robert met at least 75% of his recommended daily allowance (RDA), we need to:
1. Calculate the total intake of each vitamin from his meal.
2. Calculate the percentage of the RDA each total intake represents.
3. Check if the percentage is at least 75%.
Given the nutrient values in his meal:
- Salmon fillet (124 g)
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex]
- Vitamin C: [tex]\(0.0 mg\)[/tex]
- Vitamin E: [tex]\(0.60 mg\)[/tex]
- Boiled green beans (1 cup)
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 mg\)[/tex]
- Vitamin E: [tex]\(0.57 mg\)[/tex]
- Strawberries, sliced (1/2 cup)
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(49.0 mg\)[/tex]
- Vitamin E: [tex]\(0.42 mg\)[/tex]
### Step 1: Total Intake
Total Vitamin B12 intake:
[tex]\[ 5.87 \mu g + 0.0 \mu g + 0.0 \mu g = 5.87 \mu g \][/tex]
Total Vitamin C intake:
[tex]\[ 0.0 mg + 12.1 mg + 49.0 mg = 61.1 mg \][/tex]
Total Vitamin E intake:
[tex]\[ 0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg \][/tex]
### Step 2: Percentage of RDA
Vitamin B12:
RDA = [tex]\(2.4 \mu g\)[/tex]
[tex]\[ \left( \frac{5.87 \mu g}{2.4 \mu g} \right) \times 100 \approx 244.58\% \][/tex]
Vitamin C:
RDA = [tex]\(75 mg\)[/tex]
[tex]\[ \left( \frac{61.1 mg}{75 mg} \right) \times 100 \approx 81.47\% \][/tex]
Vitamin E:
RDA = [tex]\(15 mg\)[/tex]
[tex]\[ \left( \frac{1.59 mg}{15 mg} \right) \times 100 \approx 10.6\% \][/tex]
### Step 3: Check if percentage ≥ 75%
- For Vitamin B12, the percentage is approximately 244.58%, which is greater than 75%.
- For Vitamin C, the percentage is approximately 81.47%, which is greater than 75%.
- For Vitamin E, the percentage is approximately 10.6%, which is less than 75%.
Thus, Robert met at least 75% of his RDA for Vitamin B12 and Vitamin C.
The correct answer is:
[tex]\[ \boxed{\text{B}} \][/tex]
1. Calculate the total intake of each vitamin from his meal.
2. Calculate the percentage of the RDA each total intake represents.
3. Check if the percentage is at least 75%.
Given the nutrient values in his meal:
- Salmon fillet (124 g)
- Vitamin B12: [tex]\(5.87 \mu g\)[/tex]
- Vitamin C: [tex]\(0.0 mg\)[/tex]
- Vitamin E: [tex]\(0.60 mg\)[/tex]
- Boiled green beans (1 cup)
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(12.1 mg\)[/tex]
- Vitamin E: [tex]\(0.57 mg\)[/tex]
- Strawberries, sliced (1/2 cup)
- Vitamin B12: [tex]\(0.0 \mu g\)[/tex]
- Vitamin C: [tex]\(49.0 mg\)[/tex]
- Vitamin E: [tex]\(0.42 mg\)[/tex]
### Step 1: Total Intake
Total Vitamin B12 intake:
[tex]\[ 5.87 \mu g + 0.0 \mu g + 0.0 \mu g = 5.87 \mu g \][/tex]
Total Vitamin C intake:
[tex]\[ 0.0 mg + 12.1 mg + 49.0 mg = 61.1 mg \][/tex]
Total Vitamin E intake:
[tex]\[ 0.60 mg + 0.57 mg + 0.42 mg = 1.59 mg \][/tex]
### Step 2: Percentage of RDA
Vitamin B12:
RDA = [tex]\(2.4 \mu g\)[/tex]
[tex]\[ \left( \frac{5.87 \mu g}{2.4 \mu g} \right) \times 100 \approx 244.58\% \][/tex]
Vitamin C:
RDA = [tex]\(75 mg\)[/tex]
[tex]\[ \left( \frac{61.1 mg}{75 mg} \right) \times 100 \approx 81.47\% \][/tex]
Vitamin E:
RDA = [tex]\(15 mg\)[/tex]
[tex]\[ \left( \frac{1.59 mg}{15 mg} \right) \times 100 \approx 10.6\% \][/tex]
### Step 3: Check if percentage ≥ 75%
- For Vitamin B12, the percentage is approximately 244.58%, which is greater than 75%.
- For Vitamin C, the percentage is approximately 81.47%, which is greater than 75%.
- For Vitamin E, the percentage is approximately 10.6%, which is less than 75%.
Thus, Robert met at least 75% of his RDA for Vitamin B12 and Vitamin C.
The correct answer is:
[tex]\[ \boxed{\text{B}} \][/tex]
