Based on the activity series provided, which reactants will form products?

[tex]\[ F \ \textgreater \ Cl \ \textgreater \ Br \ \textgreater \ I \][/tex]

1. [tex]$\text{CuI}_2 + \text{Br}_2 \rightarrow $[/tex]
2. [tex]$\text{Cl}_2 + \text{AlF}_3 \rightarrow $[/tex]
3. [tex]$\text{Br}_2 + \text{NaCl} \rightarrow $[/tex]
4. [tex]$\text{CuF}_2 + \text{I}_2 \rightarrow $[/tex]

To determine which reactions will occur based on the activity series [tex]$F > Cl > Br > I$[/tex], we need to compare the reactivity of the halogens in each pair of reactants.

1. First reaction: [tex]$CuI_2 + Br_2$[/tex]

- Iodine (I) is less reactive than Bromine (Br).
- In the activity series, Bromine (Br) is more reactive than Iodine (I).
- Therefore, Bromine can replace Iodine in the compound [tex]$CuI_2$[/tex].

This reaction will occur.

2. Second reaction: [tex]$Cl_2 + AlF_3$[/tex]

- Chlorine (Cl) is less reactive than Fluorine (F).
- In the activity series, Fluorine (F) is more reactive than Chlorine (Cl).
- As a result, Chlorine will not be able to replace Fluorine in [tex]$AlF_3$[/tex].

This reaction will not occur.

3. Third reaction: [tex]$Br_2 + NaCl$[/tex]

- Bromine (Br) is less reactive than Chlorine (Cl).
- In the activity series, Chlorine (Cl) is more reactive than Bromine (Br).
- Therefore, Bromine cannot replace Chlorine in [tex]$NaCl$[/tex].

This reaction will not occur.

4. Fourth reaction: [tex]$CuF_2 + I_2$[/tex]

- Iodine (I) is less reactive than Fluorine (F).
- In the activity series, Fluorine (F) is more reactive than Iodine (I).
- Hence, Iodine cannot replace Fluorine in [tex]$CuF_2$[/tex].

This reaction will not occur.

Summarizing the results:
- The reaction [tex]$CuI_2 + Br_2$[/tex] will occur.
- The reaction [tex]$Cl_2 + AlF_3$[/tex] will not occur.
- The reaction [tex]$Br_2 + NaCl$[/tex] will not occur.
- The reaction [tex]$CuF_2 + I_2$[/tex] will not occur.

Thus, the outcomes are:
- Reaction 1: True (will occur)
- Reaction 2: False (will not occur)
- Reaction 3: False (will not occur)
- Reaction 4: False (will not occur)

The answer is [tex]$(True, False, False, False)$[/tex].