```latex
\begin{tabular}{|c|c|c|c|c|}
\hline
\multirow{2}{*}{\begin{tabular}{c}
Iron \\
Deficiency
\end{tabular}} & \multicolumn{4}{|c|}{ Age } \\
\cline { 2 - 5 }
& \begin{tabular}{l}
Less than \\
20 years
\end{tabular} & \begin{tabular}{c}
20-30 years
\end{tabular} & Above 30 years & Total \\
\hline
Yes & 41 & 37 & 24 & 102 \\
\hline
No & 109 & 43 & 46 & 198 \\
\hline
Total & 150 & 80 & 70 & 300 \\
\hline
\end{tabular}

What is the probability that a person with an iron deficiency is 20 years or older?

A. [tex]$\quad 0.23$[/tex]

B. [tex]$\quad 0.34$[/tex]

C. [tex]$\quad 0.60$[/tex]

D. [tex]$\quad 0.78$[/tex]
```



Answer :

To determine the probability that a person with an iron deficiency is aged 20 years or older, we need to follow these steps:

1. Identify the total number of people with an iron deficiency:
This information is provided in the table under the "Yes" row in the "Total" column.
[tex]\[ \text{Total number of people with iron deficiency} = 102 \][/tex]

2. Calculate the number of people with an iron deficiency who are 20 years or older:
This includes people in the age groups 20-30 and above 30.
[tex]\[ \text{Number of people aged 20-30 with iron deficiency} = 37 \][/tex]
[tex]\[ \text{Number of people aged above 30 with iron deficiency} = 24 \][/tex]
Adding these values together:
[tex]\[ \text{Number of people aged 20 or older with iron deficiency} = 37 + 24 = 61 \][/tex]

3. Calculate the probability:
The probability is calculated by dividing the number of people aged 20 or older with an iron deficiency by the total number of people with an iron deficiency.
[tex]\[ \text{Probability} = \frac{\text{Number of people aged 20 or older with iron deficiency}}{\text{Total number of people with iron deficiency}} = \frac{61}{102} \][/tex]
[tex]\[ \text{Probability} \approx 0.598 \][/tex]

So, the probability that a person with an iron deficiency is 20 years or older is approximately [tex]\( 0.60 \)[/tex].

Thus, the correct answer is:
C. [tex]\( 0.60 \)[/tex]

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