Answer :
[tex]p= \frac{2}{14}\%\\\\n=4\ [months]\\\\x=credit\cdot (1+p)^n\\ \\x=credit\cdot (1+ \frac{2}{14}\cdot \frac{1}{100})^4=credit\cdot (1+ \frac{1}{700} ) ^4=credit\cdot (\frac{701}{700} )^4\\ \\x\approx credit \cdot1.0057[/tex]
