Answer :
[tex]x^2 + 8x + 6 = 0 \\ \\ x^2 + 8x + 16 + 6 -16 =0\\ \\x^2 + 8x + 16 -10=0\\ \\x^2 + 8x + 16=10\\ \\ (x + 4)^2 = 10\\ \\x + 4 = \sqrt{ 10 } \ \ or \ \ x + 4 = - \sqrt{10} \\ \\x = \sqrt{10}-4 \ \ or \ \ x = -4 - \sqrt{10 }[/tex]
