Answer :
[tex]x+3y=9\ \ \ \Rightarrow\ \ \ 3y=-x+9\ \ \ \Rightarrow\ \ \ y=- \frac{1}{3} x+3\\\\x=0\ \ \ \Rightarrow\ \ \ y=- \frac{1}{3} \cdot0+3=0\ \ \ \Rightarrow\ \ \ point:\ (0;3)\\\\y=0\ \ \ \Rightarrow\ \ \ x+3\cdot0=9\ \ \ \Rightarrow\ \ \ x=9\ \ \ \Rightarrow\ \ \ point:\ (9,0)[/tex]
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