Answer :

f(x)=(x-1)³ = x³ -3x² +3x -1 
f(x+1) = (x+1-1)³ = x³

[tex]f(x+1)=(x+1)^3-3(x+1)^2+3(x+1)-1\\ f(x+1)=x^3+3x^2+3x+1-3(x^2+2x+1)+3x+3-1\\ f(x+1)=x^3+3x^2+6x+3-3x^2-6x-3\\ f(x+1)=x^3 \Rightarrow C[/tex]

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