Answer :
Distance of armadillo = V * t = 3t
Distance of racoon = V * (t-2) =5*(t-2)
Distance of armadillo + distance of racoon = 38
3t + 5(t-2)=38
3t + t5 - 10 =38
8t=48
t=6
The anwser is: they will be 38 km apart after 6 hours, so it is 6p.m (12a.m+6 hours)
Distance of racoon = V * (t-2) =5*(t-2)
Distance of armadillo + distance of racoon = 38
3t + 5(t-2)=38
3t + t5 - 10 =38
8t=48
t=6
The anwser is: they will be 38 km apart after 6 hours, so it is 6p.m (12a.m+6 hours)