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A cheetah is hunting. Its prey runs for 7.4 s at a constant velocity of 11.3 m/s. Starting from rest, what constant acceleration must the cheetah maintain in order to run the same distance as its prey runs in the same time?



Answer :

[tex]x=vt \\ x=at^2 \\ vt=at^2 \\ v=at \\ a=\frac{v}{t}=\frac{11.3}{7.4}=1.527m/s^2[/tex]

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