Answer :

Everest2017
Let us say T= probability of head turning up = 1/2  in one toss
H = probability of a tail turning up  = 1/2  in one toss

Then P (56 heads or more) =
           1/2^100 [ C(100,56) + C(100,57) + C(100,58) + ....
                         C(100,98) + C(100,99) + C(100,100) ]

   where C(N, R)  =  N ! / [ (N - R)! R! ]    number of occurrances of R formed from
                             N tosses.


konrad509
[tex]P(A)=\frac{100-55}{100}=\frac{45}{100}=\frac{9}{20}[/tex]

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