Answer :
Use substitution.
First we want to isolate one of the variables. Here's how you'd do that.
x +5y = -3
x = -3 -5y
Now we can just substitute -3 -5y for x in the other equation and solve for y!
3x - 2y = 8
3(-3 -5y) -2y = 8
-9 -15y -2y = 8
-9 -17y = 8
17y = 17
y = 1
And then use y = 1 in an earlier equation to find x.
x + 5y = -3
x + 5*1 = -3
x + 5 = 3
x = -2
First we want to isolate one of the variables. Here's how you'd do that.
x +5y = -3
x = -3 -5y
Now we can just substitute -3 -5y for x in the other equation and solve for y!
3x - 2y = 8
3(-3 -5y) -2y = 8
-9 -15y -2y = 8
-9 -17y = 8
17y = 17
y = 1
And then use y = 1 in an earlier equation to find x.
x + 5y = -3
x + 5*1 = -3
x + 5 = 3
x = -2
The way I would do it is the following.
Multiply x+5y=-3 by 3, making it 3x+15y=-9. Now, you can subtract the one equation from the other So, if you wrote it properly, it would look like
3x+15y=-9
-(3x-2y=8)
------------
=>17y=-17 which means y=-1. Now you can plug in y=-1 in the first equation, x+5y=-3, showing that x-5=-3, meaning x=2.
This is how I would do it. Of course, one could also solve for x in terms of y in the first equation, solving that x=-3-5y, and then substituting that into the second equation. I hope this is helpful.
Multiply x+5y=-3 by 3, making it 3x+15y=-9. Now, you can subtract the one equation from the other So, if you wrote it properly, it would look like
3x+15y=-9
-(3x-2y=8)
------------
=>17y=-17 which means y=-1. Now you can plug in y=-1 in the first equation, x+5y=-3, showing that x-5=-3, meaning x=2.
This is how I would do it. Of course, one could also solve for x in terms of y in the first equation, solving that x=-3-5y, and then substituting that into the second equation. I hope this is helpful.
