Answer :
#ANSWER#
(1+sinx/cos²x) =tan²x+1+tanx . secx
-> [(1+sinx/cos²x)] = 1/cos²x+sinx/
-> cos²x
-> = sec²x+tan x sec x
-> =tan²x+1+tanx secx
(1+sinx/cos²x) =tan²x+1+tanx . secx
-> [(1+sinx/cos²x)] = 1/cos²x+sinx/
-> cos²x
-> = sec²x+tan x sec x
-> =tan²x+1+tanx secx